如何遊玩 連續數獨
單元格之間的條表示這兩個數字是連續的
規則
標準數獨規則適用: 用數字1–9填滿每一行、列和3×3宮,每個數字恰好出現一次。
連續數獨在相鄰單元格對之間標記條紋。條紋表示這兩個單元格中的數字相差恰好為1——它們是連續的。當與負向約束(無條紋=不連續)一起使用時,這提供了整個網格中每個相鄰對的信息,創建了一個強大的約束網絡。
如需了解此謎題的來源、與相關變體的比較及策略摘要,請參閱我們的 連續數獨 變體概述.
一覽
如何解 連續數獨
常見問題
乜嘢係Consecutive Sudoku? ▾
Consecutive Sudoku is a variant where white bars appear between some adjacent cells. A white bar means those two cells hold digits that differ by exactly 1. Crucially, all consecutive adjacent pairs are marked — if there is no bar between two cells, they are guaranteed not to be consecutive.
How does the no-bar constraint work? ▾
Every adjacent pair that is NOT consecutive has no bar. This negative information is extremely powerful — it eliminates all consecutive digit pairs from unmarked cell boundaries. Experienced players apply no-bar eliminations as aggressively as the positive bar clues.
What pairs count as consecutive? ▾
Consecutive digits differ by exactly 1: 1&2, 2&3, 3&4, 4&5, 5&6, 6&7, 7&8, 8&9. The constraint applies to horizontally and vertically adjacent cells only — diagonal neighbours are not considered.
What is the best first move in Consecutive Sudoku? ▾
Look for long chains of consecutive bars — a chain of four bars forces four consecutive digits in those five cells. Also, digits 1 and 9 can only be consecutive with 2 and 8 respectively, so any cell surrounded by no-bar neighbours cannot hold 1 or 9 unless those specific partners are available nearby.
Is Consecutive Sudoku harder than regular Sudoku? ▾
At easy difficulty it is comparable to medium classic Sudoku. The bars and no-bars together provide a dense constraint web that makes early eliminations fast. Hard and expert puzzles become much more demanding as bar chains grow longer and interact with more rows, columns, and boxes.
How long does Consecutive Sudoku take to solve? ▾
Easy puzzles take 8–18 minutes. Medium puzzles run 18–35 minutes. Hard puzzles average 35–65 minutes and expert puzzles often exceed 90 minutes. Applying both bar and no-bar logic simultaneously is the key to efficient solving at all levels.